Question

what is the derivative of g(x) = cosh(ln(x))

Answer 1

Is that cos with the hyperbolic thing? or is that h * ln(x)?

Answer 2

with the hyperbolic

Answer 3

g'(x) = cosh(ln(x)) * 1/x

Answer 4

Had to find out the derivative of cosh, but it's apparently just cosh.

Answer 5

According to this:
http://www.ucl.ac.uk/Mathematics/geomath/level2/hyper/hy4.html

Answer 6

isnt it sinh?

Answer 7

Crap, I keep looking at things wrong today...
Yes, you're right:
g'(x) = sinh(ln(x)) * 1/x

Answer 8

I hope that's right, it's been a while since I last differentiated. :D

Answer 9

Check that out on your calculator.

Answer 10

thank u! ya it is right

Answer 11

Woot :D Thanks for the +1

Answer 12

haha np