Question

I NEED MAJOR HELP IM TRYING TO SOLVE EQUATIONS WITH EXPONENTS


(X+1)^3/2=64

Answer 1

hey

Answer 2

x^3 + 1 /2 = 64
Find the greatest common denominator, so 2 x 64 = 128
x^3 + 1 = 128 ( cancel out denominators)
x^3 = 127

Answer 3

I may be wrong however

Answer 4

yeah, you are wrong.. :)

Answer 5

lol thought so

Answer 6

multiply both sides by 2. (x+1)^3 = 128. to get rid of the exponents, take the cube root of both sides. x+1 = cbrt (128). x = cbrt(128) - 1

Answer 7

that's assuming the 2 is not part of the exponent

Answer 8

Ahh nicely done man I'm only 15 so forgot to cube root :P

Answer 9

no problem i'm older than that be careful about giving out help if you're not sure though :)

Answer 10

SO WHATS THE ANSWER
A)15B)511C)17D)21

Answer 11

we should verify what the equation actually is because the way it is is confusing.

Answer 12

(X+1)^(3/2)=64 ?

or

[(X+1)^3]/2=64

Answer 13

(X+1)^2/3=64

Answer 14

thats what you had typed before, and it is ambiguous. Pick one of the ones I offered please.

Answer 15

THE FIRST

Answer 16

ok...

(X+1)^(3/2)=64

ln((x+1)^(3/2)) = ln(64)

(3/2) ln(x+1) = ln(64)

log2(x+1) = (2/3) log2(64)

log2(x+1) = (2/3) (6)

log2(x+1) = 4

x+1 = 2^4

x+1 = 16

x = 15

if I did it all right :)

Answer 17

THANKS SO MUCH