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determine the area between the curves y=abs(x) and y=x^2-2
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hey, how's it going
terribly
haha, sorry about that, well the tricky part of this is realizing that abs(x) is just -x when x <0, and x when x>0
so you can split it up into two integrations on either side of the y-axis
This will be a pain to type out...good luck bobeuclid!
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does that help you akandy?
yeah i think so thanks a bunch
it's symmetric so the two halves should come out to the same area, if they don't you've probably made a mistake
I get 20/3...anyone else?
yeah thats what i got too
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