Question

If w=x^2+y-z+sin t & x+y=t , then how to find part.dervivative of w wrt y ? plz click to find more.....

Answer 1

\[w = x ^{2} + y - z + \sin(t)\]
\[x + y = t\]
Sorry which derivative are you looking for?

Answer 2

we have to find \[(dough w/dough y)_{x,z}\].partial derivative

Answer 3

I'm honestly not sure what you mean by that notation.

Answer 4

there's no notation here, consider dough = d
(dw/dx)\[_{x,z}\]

Answer 5

(\[(dw/dx)_{x,z}\] what does this x,z mean here?

Answer 6

sry , it is \[(dw/dy)_{x,z}\]

Answer 7

use \partial to get \[\partial\] if you like

Answer 8

thanks eb... can u temme wat foes 'x,z' mean here?

Answer 9

\[(\partial w/ \partial y)_{x,z}\] --------this is the actual notation

Answer 10

Okay I think that means find the derivative of w with respect to y, and evaluate at x,z?
Not exactly sure

Answer 11

i wanted to know what this x,z means...i guess those are independent variables? is it?

Answer 12

w=x2+y−z+sin(t)
x+y=t

w=x2+y−z+sin(x+y)

assuming w=f(x,y,z)
(dw/dy) =0+1+0+cos(x+y)
=1+Cos(x+y)