Question

if h,s, V be the height, Curved surface area and volume of a cone respectively then 3piVh^3 - s^2h^2 + 9V^2 is:


NOTE PI = 22/7 or 3.14

Answer 1

sstarica do u want options

Answer 2

you mean \[(3\pi Vh)^3 - s^2h^2 + 9V^2\]

so what's the problem?

Answer 3

no sstarica

Answer 4

it is only h^3

Answer 5

so you have to solve it

Answer 6

then why do you have 3 piV multiplied by h?

Answer 7

i dodn't undeand
rst

Answer 8

you have 3piVh ^3 right?

Answer 9

yes of course

Answer 10

you want to solve the equation?

Answer 11

yes

Answer 12

but your question is unfortunately unclear, what is excatly that you want?

Answer 13

SEE i am giving you V= 1/3 * pi * r^2 * h

Answer 14

lol

Answer 15

AND S = pi^2r^2(root of (r^2 + h^2))

Answer 16

so you don't know the answer of only 8th standard

Answer 17

no now, I got you. :)

Answer 18

oh k

Answer 19

ANSWER IT

Answer 20

excuse me, you're the one who asked for help, why are you being so boiled up? It's rude, please be polite.

Answer 21

okey

Answer 22

all you have to do is substitute V and S in the equation and simplify.

Answer 23

THIS IS THE PROBLEM THAT I M FACING THE ANSWER IS NOT IN OPTIONS

Answer 24

and when you do that you get in the end.\[\pi^2r^2h^4 - 4\pi r^4h^2(r^2 + h^2) + 1/3 \pi r^2h\]

Answer 25

yes i did that

Answer 26

ofcourse you won't get it corret in the first place, try again.

What are the options, tell me?

Answer 27

okey i m giving the options

Answer 28

1) option - 2

Answer 29

2) option - 0

Answer 30

3) option - 2pi

Answer 31

4) option - 3(pi)^2

Answer 32

I've made a mistake, in the end of the answer I gave you above it's supposed to be \[3\pi r^2h\] and note 1/3 pir^2h

Answer 33

not*

Answer 34

the answer is 0 !

Answer 35

here the solution is :

first you'll substitute the given in the formula and you will end up with this:
\[\pi^2 r^2h^4 - 4 \pi^2r^4h^2(r^2 + h^2) + \pi^2r^4h^2\]

then simplify, it's a long step but in the end you will end up with :
\[-3\pi^2r^2h^4 - 3\pi^2r^2h^2\]
= \[-3\pi^2h^2(r^2h^2 - r^2h^2)\]
= \[-3\pi^2h^2\] x 0
= 0

That's it :)

Answer 36

wait that's wrong >_<

Answer 37

this has caused me a headache._.