Question

(square root of 2)^(x+4)=4^x

I just want to know how to get the bases to be the same. Do you square both sides, or do I "arrange" the right side of the equation to get the bases to be the same?

Answer 1

sqrt(2)^(x+4) = 4^x

square both sides to get rid of the sqrt sign

Answer 2

[sqrt(2)^(x+4)]^2 = [sqrt(2)^2]^(x+4)

[4^x]^2 = [4^2]^x

Answer 3

we get:

2^(x+4) = 4^2x

Answer 4

I get x=4/3

Answer 5

I wrote both sides as base sqrt(2)

Answer 6

4=(sqrt(2))^4

Answer 7

(sqrt(2))^(x+4)=(sqrt(2))^(4x)

Answer 8

so x+4=4x