Question

csc t/sec^2t*sin t-sin t cost^2t/cos^2t

Answer 1

what are we doing?

Answer 2

simplifying?

Answer 3

oh sorry. yes simplifying

Answer 4

Put everything in terms of sin(t) and cos(t)...I can't quite identify if you're multiplying the denominator of the first term by sin(t) or the whole fraction. Could you please clarify with the equation editor as a response?

Answer 5

yes i agree with modulus. i cant read.

Answer 6

okay cool so cscx=1/sinx and 1/(secx)^2=(cosx)^2

Answer 7

We have now that [(cost)^2/sint]*[(sint-sint(cost)^2/(cost)^2]

Answer 8

we see that (cost)^2 cancel giving us (sint-sint(cost)^2)/sint

Answer 9

But oh mine there is a sint in each term so we can cancel a sint from each term because sint/sint=1: (1-(cost)^2)/1

Answer 10

But (sint)^2+(cost)^2=1 so 1-(cost)^2=(sint)^2

Answer 11

thanks