Question

how do you solve x^2-2xy=6 by implicit differentiation?

Answer 1

\[= 2x -2yy'\]\[y' = -2x/2y \]

\[y' = -\]

Answer 2

y' = -x/y *

Answer 3

correct me if I'm wrong ^_^

Answer 4

dy/dx(x^2-2xy=6)
= 2x(dx)-(2y(dx)+2x(dy)=0
=2x(dx)-2y(dx)-2x(dy)=0
=(dx)(2x-2y)=2x(dy)
=(2x-2y)=2x(dy/dx)
(dy/dx)=(2x-2y)/(2x)
(dy/dx)=(x-y)/(x)

Answer 5

lol, right! I forgot abt the 2xy, arman's answer is correct ^_^

Answer 6

the book says the answer is 1- y/x

Answer 7

yeah same thing

Answer 8

hmm, let me write it down on paper

Answer 9

(x-y)/(x)
=(x/x)-(y/x)
=1-(y/x)

Answer 10

exactly

Answer 11

:-)

Answer 12

did you understand it lefty? :)

Answer 13

lots of use of distribution, and dont forget your product rule! :O

Answer 14

you got that right, how can I forget such thing >_<

Answer 15

yup, your above walkthrough i will figure out. thank you guys

Answer 16

thanks to arman :) good luck!

Answer 17

aha no worries, i messed up my quotient rule for the first 50+ pages of problem sets i did, i was devastated when i found out

Answer 18

yep yep good lucck

Answer 19

yeah it makes it even tougher my professor is a Romanian immigrant