Question

I am going skydiving. If I jump from 15000 feet, what will be my speed at 1500 feet?

Answer 1

where are you skydiving for a start?

Answer 2

assuming it is Earth and assuming that acceleration due to gravity is constant (9.8) then you use v^2=u^2+2as

Answer 3

problema solved by @maths, dd you understand it saurav? ^_^

Answer 4

did*

Answer 5

yes, it is very important to know if it is earth or other planet, because the acceleration due to gravity is different in different places in the universe

Answer 6

that's true :)

Answer 7

yeah thanks ... I would also need to convert my distance in meters first! It will be scary fast though!!

Answer 8

LOL! good luck :)

Answer 9

well, the formula wont help

Answer 10

you forgot resistance from air

Answer 11

which keeps increasing as your velocity is increasing

Answer 12

some relief to hear that!

Answer 13

so, you got to use some extra formulas, and you got to know your surface area, and the friction index of your clothing material in relation to air

Answer 14

calculus wont hurt for exact calculations

Answer 15

well as the question does not explicitly say which model for air resistance is being used, i think it is logical to disregard air resistance unless you are a university level physicist

Answer 16

anyway, have fun, my friend did it a year back, while he was in Africa :) He sayed he almosed shi**d his pants.

Answer 17

But after landing, he was really happy.

Answer 18

Can I not calculate some negative acceleration due to resistance? But how would I do that?

Answer 19

I also want to do skydiving, but now i am busy with some piloting stuf

Answer 20

it would simply decrease your overall accelaration up to a point (terminal velocity) when your velocity is constant

Answer 21

cool @BecomeMyFan=D !

Answer 22

Speed at 1500 feet will depend on your parachute. It better be open at 1500 feet!!! lol

Answer 23

Hopefully slow enough to survive !!

Answer 24

Truthfully with the parachute, you couldn't ignore air resistance. I think you would have to do this in two parts, first ignore the air resistance for the period the chute is not opened, then a new acelleration formula would be needed when chute is opened. There is a big change in acceleration when that chute pops.