Question

factor out the trinomial.
h=-2tsquared+87t+90

Answer 1

well i know from there what you do is
\[-(2t ^{2}-87t-90)\]
then you multiply 90 and 2t squared which gives you -180 then what you have to do is think what times what vies me 180 but also when u add/subtract them it gives you 87 and i dont know those two number

Answer 2

Just use the quadratic equation

\[t = [-b \pm \sqrt{b^2-4ac}]/2a\]

Where a=-2, b=87, c=90. That will give you your two values for t when h=0 allowing you to rewrite the equation as
\[h = (t-t_1)(t-t_2)\]

Answer 3

i never learned that i just need two number that multiply and equal 180 but when u add/subtract those two numbers in equals 16

Answer 4

Are you sure the middle term isn't 88t?

Answer 5

im sure

Answer 6

Then you don't get nice numbers. If it were 88t you'd have:

h=-(2t+2)(t-45)
As it is here, you get
h=(t + 1.0109863582402774)(t-44.510986358240274)

Answer 7

oh woah i will just ask my teacher tomorrow

Answer 8

thank you though!

Answer 9

oh and also what times what equals 1536 but when u add/subtract them it eguals -16