Question

x^5+x^2/x^-2 simplifiy

Answer 1

negative exponents are reciprocals, so if its negative exponent just put it on the other side of the fraction:

x^5 + x^2/x^-2 =
(x^5+x^2)(x^2)=
x^7+x^4

Answer 2

another way to look at it, is that when you divide exponents with the same bases (base is x in this case) you subtract the exponents value from the numerator:

x^5+x^2/x^-2=
x^(5-[-2])+x^(2-[-2])=
x^(5+2)+x^(2+2)=
x^7+x^4

Answer 3

so theres: \[x^m \div x^{-n} = x^m \times x^{n} \]

and:
\[x^m \div x^{n} = x^{m-n}\]

Answer 4

=x^5+x^2+2
=x^5+x^4
=x^4(x+1)