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lim (x^2) / (cos4x - cos9x) as x->0
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what happens when you plug zero into the equation?
Indeterminate form. 0/0
right, so what can we do from here?
L'Hospital Rule.
right, and what do we get from that?
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Nvm. L'Hospital wont work in this situation.
why not?
It is still indeterminate. sin(0)=0
right, so we can do L'Hopitals rule again
True. I forgot about it.
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after the second derivative you are left with 2 in the numerator, and cosines in the denominator, so you should be good from there
when you do L'Hopitals rule again rather
Do you have an answer?
yes 0.0307692
yes, 0.030769
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also 2/65
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