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Mathematics 15 Online
OpenStudy (anonymous):

lim (x^2) / (cos4x - cos9x) as x->0

OpenStudy (anonymous):

what happens when you plug zero into the equation?

OpenStudy (anonymous):

Indeterminate form. 0/0

OpenStudy (anonymous):

right, so what can we do from here?

OpenStudy (anonymous):

L'Hospital Rule.

OpenStudy (anonymous):

right, and what do we get from that?

OpenStudy (anonymous):

Nvm. L'Hospital wont work in this situation.

OpenStudy (anonymous):

why not?

OpenStudy (anonymous):

It is still indeterminate. sin(0)=0

OpenStudy (anonymous):

right, so we can do L'Hopitals rule again

OpenStudy (anonymous):

True. I forgot about it.

OpenStudy (anonymous):

after the second derivative you are left with 2 in the numerator, and cosines in the denominator, so you should be good from there

OpenStudy (anonymous):

when you do L'Hopitals rule again rather

OpenStudy (anonymous):

Do you have an answer?

OpenStudy (anonymous):

yes 0.0307692

OpenStudy (anonymous):

yes, 0.030769

OpenStudy (anonymous):

also 2/65

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