Question

(3x)/(x+1)=12/(x^2-1)+(x+4)/(x-1)

Answer 1

Let's write it down first:\[= (3x/x+1) - (12/(x+1)(x-1)) - (x+4/x-1)\]

multiply by x + 1 and x-1 to get the same denominator and you'll get :

\[= [3x(x-1)/(x+1)] - [12/(x-1)(x+1)] + [(x+4)(x+1)/(x-1)(x+1)] \]
\[= (3x^2 - 3x -12 - x^2 - 5x - 4)/(x-1)(x+1)\]
\[= (2x^2 - 8x -16)/(x+1)(x-1)\]

Answer 2

from the 2nd line it's [(x+14)(x+1)/(x+1)(x-1)] sorry ^^"

hope it's clear now ^_^

Answer 3

Were you to solve for x. There is an equal sign in that equation. As you can see it works down to a quadratic equation divided by another second degree equation