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solve the diff eq dy\dx+3x^2*y=x^5*e^x^3
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this follows the same method
as above
Yes, Here u Chose U as U = e^int( 3x^2)
\[U \times y \int\limits_{}^{} U \times x ^{5\times}e ^{x ^{3}}\]
no...not required, u can take u=x^3
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aha, count it as a seperabel?
after simplification, the eq. becomes \[y dy = (1/3) (x^3 . e^ (x^3))
ignore \[ in the beginning
so in RHS, u can take u=x^3 and solve....okay?
Are u sure u have done right ..
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hmmm
aren't you getting the same?
noo?
\[Dy \div Dx + 3x ^{2} y=x ^{5} e ^{x ^{3}}\]
he means i hope..
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yeah its the same eq the ans is \[12y=e ^{x ^{3}}(2x^3-1)+ce ^{-x ^{3}}\] how to get that?
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