Question

determine two values of b that will make 64xcubed+bx+16 a perfect square trinomial

Answer 1

\[64x^3+b*x+16\]

Answer 2

a perfect square trinomial is a square of a binomial: \[(a+b)^2\]

Answer 3

if i assume the equation to be 64x^2 + b*x + 16 --> (a + b)^2 = a^2 + 2*a*b + b^2

Answer 4

ok b^2 = 16, so \[\sqrt{16} = \pm\]

Answer 5

+/- 4

Answer 6

a^2 = 64x^2, so let's keep a=8x.....now for the 2*a*b portion. we have a and b, but each value can be positive or negative....so the value are +/- 4 and +/- 8.

Answer 7

so 2*a*b

Answer 8

from your equation: [bx] = 2*a*b

Answer 9

so b can vary between 2*(+/-4)*(+/-8)