mlbmarlins2011 Pupil (0 fans) say you purchased a piece of land 150 meters by 10,000 meters. The thickness of the reservoir rock that you hope contains petroleum is 9 meters. Calculate the total volume of your possible oil field in cubic meters. If the answer is: 103,500,000 cubic meters than how do i answer this next question? Not all of this thickness will be petroleum. Petroleum is only found in the pore spaces of rock, and some of those pore spaces may contain both water and oil. Assuming a 20% pore space, how much volume o
volume of petroleum can you now optimistically expect?
you can imagine your land as a solid rectangle , the given is the following: h= 150 m L = 10,000 m w = 9 m and the general formula of the Rectangle's volume is : \[V = Lwh\] \[V = (10,000)(150)(9) \] \[V = 13500000 m^3\]
that's your volume ^_^
the second question is incomplete, can you re-type it please? ^_^
The second question is: Not all of this thickness will be petroleum. Petroleum is only found in the pore spaces of rock, and some of those pore spaces may contain both water and oil. Assuming a 20% pore space, how much volume of petroleum can you now optimistically expect?
I think you have to mulitply 20% by the volume and you'll get:\[V= (13500000)(20/100)\]\[V = 2700000 m^3\] Correct me if I'm wrong :)
That sounds right and then it goes on to say: The estimate you calculated was for both oil and water in the pore spaces. Assume 35% is oil and the rest is water. Now how much petroleum can you expect?
Alright, you have found the volume for both the oil and water in the pore, so subtract it from 35/100 :) I guess
wait!
if 20% is both oil and water and 35% is just oil, then add both and subtract from 100% and you'll get the petroleum percentage
so 35% + 20% = 55% 100% -55% = 45% is petroleum
and 35% -20% = 15% is water
lol, hold on: water = 15% oil = 35% oil + water = 45% petroleum = 100% - 45% = 55% Correct me if I'm wrong ^_^
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