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relative rate of change for f(x)= 5x - xlnx
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Same deal as before. From the definition,\[\frac{f'(x)}{f(x)}=\frac{5-(\ln x+1)}{5x-x \ln x}=\frac{4-\ln x}{x(5-\ln x)}\]
Are you having trouble with taking the derivative?
yeah i wasnt sure how to get the derivative.
jsut when you have ln
I'm thinking it's the xlnx bit?
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\[\frac{d}{dx}x \ln x=x \frac{d}{dx}\ln x+\ln x \frac{d}{dx}x=x \times \frac{1}{x}+\ln x \times 1\]\[=1+\ln x\]
So the entire derivative in the numerator is\[f'(x)=5-(1+\ln x)=4-\ln x\]
thanks
no worries
im trying to correct this test and this class is killing me
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