lim of (x^3-13x+12)/(x^3-14x+15) as x approaches 3 without using L hopital's rule. :( hope you can help me guys.
dude none of them are going to help you
:( maybe you're right. </3
Don't be so pessimistic. Did you try actually dividing those polynomials as far as you can?
you have to divide it so that when you plug x=3 , the result is not 0/0
i still get 0/0 guys
by using L hopital's rule i get 14/13. but the question must be solved w/o using it. :(
usually, there will be a common factor between the denominator and the numerator, but i can't factorize those polynomial
this problem sure is hard. xD
If a polynomial has a root "a", there is a factor (x-a) in it!
i don't get your point bro.
i got the common factor ! it's gonna be -> (x-3)(x^2 + 3x -4) / (x-3)(x^2+3x-5)
you can eliminate x-3, then plug x=3 you'll get -> (9+9-4)/(9+9-5) = 14/13
whoa! thanks din!!!
you're welcome btw, i got the common factor by using Horner's method
I'm not familiar with it. can you please give some background :D
i'll just google it. :)) thanks din for the info. ;)
:)
lol! it's just synthetic division :))
haha in my school we usually call it horner's method
The denominator and the numerator are both 0 when x = 3, what does that tell you?
it means that the function is in indeterminate form :)
obtaining 0/0 in a function doesn't that it has no limit. :)
what the answer in this question? please. I help me out 😉
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