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Mathematics 16 Online
OpenStudy (anonymous):

lim of (x^3-13x+12)/(x^3-14x+15) as x approaches 3 without using L hopital's rule. :( hope you can help me guys.

OpenStudy (anonymous):

dude none of them are going to help you

OpenStudy (anonymous):

:( maybe you're right. </3

OpenStudy (nowhereman):

Don't be so pessimistic. Did you try actually dividing those polynomials as far as you can?

OpenStudy (anonymous):

you have to divide it so that when you plug x=3 , the result is not 0/0

OpenStudy (anonymous):

i still get 0/0 guys

OpenStudy (anonymous):

by using L hopital's rule i get 14/13. but the question must be solved w/o using it. :(

OpenStudy (anonymous):

usually, there will be a common factor between the denominator and the numerator, but i can't factorize those polynomial

OpenStudy (anonymous):

this problem sure is hard. xD

OpenStudy (nowhereman):

If a polynomial has a root "a", there is a factor (x-a) in it!

OpenStudy (anonymous):

i don't get your point bro.

OpenStudy (anonymous):

i got the common factor ! it's gonna be -> (x-3)(x^2 + 3x -4) / (x-3)(x^2+3x-5)

OpenStudy (anonymous):

you can eliminate x-3, then plug x=3 you'll get -> (9+9-4)/(9+9-5) = 14/13

OpenStudy (anonymous):

whoa! thanks din!!!

OpenStudy (anonymous):

you're welcome btw, i got the common factor by using Horner's method

OpenStudy (anonymous):

I'm not familiar with it. can you please give some background :D

OpenStudy (anonymous):

i'll just google it. :)) thanks din for the info. ;)

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

lol! it's just synthetic division :))

OpenStudy (anonymous):

haha in my school we usually call it horner's method

OpenStudy (anonymous):

The denominator and the numerator are both 0 when x = 3, what does that tell you?

OpenStudy (anonymous):

it means that the function is in indeterminate form :)

OpenStudy (anonymous):

obtaining 0/0 in a function doesn't that it has no limit. :)

OpenStudy (anonymous):

what the answer in this question? please. I help me out 😉

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