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Mathematics 19 Online
OpenStudy (anonymous):

y'' for y= (x^2+9)^4

OpenStudy (anonymous):

\[8(x^2+9)^3+48x(x^2+9)^2\]

OpenStudy (anonymous):

awesome thank you

OpenStudy (anonymous):

could you show me y' for this so i can see how you got y''

OpenStudy (anonymous):

\[8x(x^2+9)^3\]

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

No Problem

OpenStudy (anonymous):

could you help me on another?

OpenStudy (anonymous):

Sure

OpenStudy (anonymous):

y'' for y= ln x/x^2

OpenStudy (anonymous):

I am horrible when it come to ln in problems

OpenStudy (anonymous):

\[-3x^(-4)+6lnx(x^(-4))+4x^(-4)\]

OpenStudy (anonymous):

ooops

OpenStudy (anonymous):

ha ha ha

OpenStudy (anonymous):

-3x^(-4)+6x^(-4)lnx+4x^(-4)

OpenStudy (anonymous):

could you show me how to do this?

OpenStudy (anonymous):

\[y=lnx(x^{-2})\] Then you use product rule

OpenStudy (anonymous):

okay..so then thats how you got the final answer

OpenStudy (anonymous):

y' = x^(-3)-2x^(-3)lnx

OpenStudy (anonymous):

and then you differentiate it again? do u know how to do that?

OpenStudy (anonymous):

yes then you get....

OpenStudy (anonymous):

-3x^(-4)+6x^(-4)lnx+4x^(-4)

OpenStudy (anonymous):

-3x^-4 + 6x^-4 lnx ?

OpenStudy (anonymous):

remember to use product rule for x^(-3)lnx

OpenStudy (anonymous):

where are you getting the last part?

OpenStudy (anonymous):

you forgot to use product rule for lnx(x^(-3))

OpenStudy (anonymous):

oh okay now im with you. thanks

OpenStudy (anonymous):

welcome

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