find the slope of the tangent line to the curve -1x^2-4xy-2y^3=92 at point
(-2,-4)

Question

find the slope of the tangent line to the curve -1x^2-4xy-2y^3=92 at point 
(-2,-4)

anonymous · Answer

Use some implicit differentiation, differentiate the function, solve for dy/dx and plug in the points (-2,-4). Then, just use y-y1=m(x-x1) to find the tangent line.

anonymous · Answer

yes i get the concept and i did all that but, it's saying i have the wrong answer :(

anonymous · Answer

Hm...can you use the equation feature to clean up the function for me? Then I'll try it out and tell you what I get. :)

anonymous · Answer

i got -2x-4x y'+4x' y-6y^2 y'=0

anonymous · Answer

Mainly the first term...is it -x^2?

anonymous · Answer

yes but they wrote it as -1x^2

anonymous · Answer

i got y'=2x-4y/-4x-6y^2

anonymous · Answer

sot sure if that's right

anonymous · Answer

I'm getting this:
$$-2x - 4x*\frac{dy}{dx} - 4y - 6y^2\frac{dy}{dx} = 0$$$$-2x-4y = 4x \frac{dy}{dx} + 6y^2\frac{dy}{dx}$$$$\frac{dy}{dx} = \frac{-2x-4y}{4x+6y^2}.$$

anonymous · Answer

sorry i couldn't read what u got

anonymous · Answer

...hm?

anonymous · Answer

sorry what u sent came up as a math processing error on my screen, but i g2g so thanks anyways

anonymous · Answer

maybe next time