Question

what is the maximums and minimums of the equation y=2.657x^3 + -1.48x^2 + .2819x + 7.7E-14?

Answer 1

thats kinda complicated to figure out you should go to http://www.wolframalpha.com

Answer 2

your welcome

Answer 3

if this is a y or f(x) then differentiate it then equaled it to zero and find its roots, that rot will be your max or min point..just plug it into your original equation....

Answer 4

Y'=7.7971X^2 -2.96X +.2819.....NOW THIS IS A QUADRATIC EQUATION,.YOU CAN SOLVE FOR THE ROOTS NOW

Answer 5

this is supposed to be a quartic...

Answer 6

no,,, quartic eq starts at say x^4,....cubic is x^3.... quadratic is x^2

Answer 7

what do i do after i derive the equation to find the minimums and maximums?

Answer 8

this does start at x^4...... -1.28x4 + -33.36x3 + -323.41x2 + -1384.63x + -2206.60

Answer 9

no it doesn't

Answer 10

it's 2.657x^3.....

Answer 11

hehe look up at your prob here atart at y=x^3 it a cubic eq rt?

Answer 12

wait who are you talking to?

Answer 13

after you done the derivative, the derivative is now a quadratic y'= ...x^2

Answer 14

then how do you find the minimums and maximums

Answer 15

ok ..you equate the derivative to zero and find its roots

Answer 16

that roots will become you max or min of your original equation

Answer 17

what is the answer after equating the derivative

Answer 18

ok, to find the roots, do you know the quadratic formila?

Answer 19

x=(-b+\[\sqrt{?}\]b2-4ac)2a

Answer 20

im sorry my pc equation writer does not write well
here you a=7.797.....b=-2.96...c= .2819

Answer 21

x=(2.96+-\[\sqrt{?}\]-.0303)/15.594

Answer 22

did you get it? the roots are imaginaries...do you know what is imaginary number?

Answer 23

obviously... a number that's imaginary like i for example or e

Answer 24

im just asking what are the points (max and min) for my equation

Answer 25

no...any square root of a negative number are imaginary number like square root of -1, sqrot of -2, squroot of - numbers

Answer 26

ok here the simplest way of geting the derivative roots is to graph the derivative and approximate its roots..did you get what i mean?

Answer 27

Y'=7.7971X^2 -2.96X +.2819.....graph this and find its root or zeroes

Answer 28

here one root is 0.2819...you plug it in your orig equation
y=2.657(.2819)^3 + -1.48(.2819)^2 + .2819(.2819)+ 7.7E-14=?

Answer 29

min y=0.02137744667

Answer 30

i graph it rt now and found the root x=0.8948 now you can plug it in to your orig prob.

Answer 31

your max or min y=0.9708296575

Answer 32

sorry never mind that root x=.2819 or min y=.02137744667....thats a mistake,, graph it and found that the max or min y=.9708296575