Question

RATIO OF ELECTRIC FIELD.

Please solve Question 6 in the attached image.

The answer is B.) 2:1

Answer 1

Here is the question.

Answer 2

after sharing the charge, q1:q2 =1:2
r'\[r'^{2}:r ^{2}=4:1 Ep:Eq=2:1 (E=kq/r ^{2)}\]
\[(E=kq/r ^{2})\] for E at the surface of a conducting charged sphere

Answer 3

Thank you for replying.

I managed to solve it by reading the OCW Scholar notes.