Find a vector that the same direction as −2i + 4j+ 2k but that has length 6.
desperately waiting for ur reply...so fed up with this problem right now !!! help
hi guys
do share ur views on this plss
i am new here, on this site, looks fun
surely it is !!! nothing lesser than a boon to the students !!! getting live help for free is just awesome
feels like v r a community sharing its knowledge
I am graduating highschool this spring
congrats bro !!!
the only bad thing is that me and my boyfriend are going to different universities :(
which uni r u in ?
Carnegie Mellon University
what degree wer u in ?
Computer Science, I know this sounds strange because I am a girl, but I LOVE computer science and programming
thats good.....computers r not just monopoly of boyzzz
:)
may i ask ur name ?
ankur, you still need an answer?
You just need to find the unit vector of u and multiply it by 6
ah got it !!! cheers !!!
Cool
\[|-2i+4j+2k|=\sqrt{(-2)^2+4^2+2^2}=2\sqrt{6}\] \[\vec{a}=\alpha(-2i+4j+2k)\quad,\quad\alpha=\frac{6}{2\sqrt{6}}=\frac{\sqrt{6}}{2}\] \[vec{a}=\frac{\sqrt{6}}{2}(-2i+4j+2k)=-\sqrt{6}i+2\sqrt{6}j+\sqrt{6}k\]
hey one more short question
?
unit vector that is perpendicular to the xz-plane
(1,0,0) lies in x, (0,0,1) lies in z, so (0,1,0) will lie in y which is perpendicular to xz.
@nikwist : could you please tell how do u type square roots like this on screen?
and it's a unit vector.
u r so intelligent !!! no wonder you have so many fans !!! thanx a lot again
np...fan me if you haven't :)
i have...do u have any idea how nikwist wrote his answers like that above?
Yes, go into equation editor below, and there's a set of boxes to the right you can use. You can also type, sqrt{x} directly into the equation line to get\[\sqrt{x}\]
cheers !!! u r really a lifesaver
np :D
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