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Indicate the equation of the given line in standard form. The line containing the diagonal of a square whose vertices are A(-3, 3), B(3, 3), C(3, -3), and D(-3, -3). Find two equations, one for each diagonal. (oh goodness, I'm not good with multiple vertices *facepalm*)
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ok, first you would find the slope of BD. which is rise/run - 3-(-3)/3-(-3). that equals 1. so the slope of BD is 1. we would first try to make the line into y=mx+b form. so we use B (3,3) to sub in. 3=1(3)+b. solve, and find b is 0. so the equation for diag. BD is y=1x+0. convert to standard form Ax+By=C. To solve for the other diag. you would do the same thing.
sorry, same thing with the slope being the negative reciprocal of the first.
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