Indicate the equation of the given line in standard form.
The line containing the diagonal of a square whose vertices are A(-3, 3), B(3, 3), C(3, -3), and D(-3, -3). Find two equations, one for each diagonal.

(oh goodness, I'm not good with multiple vertices *facepalm*)

Question

Indicate the equation of the given line in standard form.
The line containing the diagonal of a square whose vertices are A(-3, 3), B(3, 3), C(3, -3), and D(-3, -3). Find two equations, one for each diagonal.

(oh goodness, I'm not good with multiple vertices *facepalm*)

anonymous · Answer

ok, first you would find the slope of BD. which is rise/run - 3-(-3)/3-（-3）. that equals 1. so the slope of BD is 1. we would first try to make the line into y=mx+b form. so we use B (3,3) to sub in. 3=1(3)+b. solve, and find b is 0. so the equation for diag. BD is y=1x+0. convert to standard form Ax+By=C. To solve for the other diag. you would do the same thing.

anonymous · Answer

sorry, same thing with the slope being the negative reciprocal of the first.