Question

how would you solve this problem in simplest form: x with power of 3 divided by 2y power of 2 times 6y power of 4 divided by xy?

Answer 1

\[x ^{3}\div(2y)^{2} * (6y)^{4}\div xy\]

Answer 2

But written as two fractions... is that what you mean?

Answer 3

or
\[2y ^{2}\]

Answer 4

and
\[6y ^{4}\]

Answer 5

in the 2y problem the y is to the power of 2 and in 6y the y is to the power of 4

Answer 6

OK.. So here is a long way of thinking about this first.

Answer 7

x^3 = x * x * x
2y^2 = 2 * y * y
6y^4 = 2 * 3 * y * y * y * y
xy = x * y

Do you agree with this?

Answer 8

yes

Answer 9

So we have

x * x * x 2 * 3 * y * y * y * y
-------- * ----------------
2 * y * y x * y

OK?

Answer 10

ok

Answer 11

When everything is being multiplied... You can cancel out anything on the top with anything on the bottom...

Answer 12

So I would put a slash thru the 2 on the top and then put a slash thru the 2 on the bottom.


What else do you see?

Answer 13

cancel out any "like" terms top to bottom ;)

Answer 14

oops you are so right amistre64.. I was thinking it but forgot to type it.

Answer 15

are you talking about just the 2's I'm confused.

Answer 16

No... what else is alike...

I see an x on the bottom and an x on top... put slashes thru those.

I see three y's on the bottom that can cancel with three y's on top.

Do you see that?

Answer 17

that should leave you with
3x^2y x^2 is x to the 2nd power.

Answer 18

yes I just did that now do I cross multiply then divide to get the answer?

Answer 19

Well. you don't cross multiply... You basically cancel like terms top and bottom and then whatever is left over on top stays on top and whatever is left over on the bottom stays on the bottom (what I mean by left over is that it doesn't get cancelled out)

There is a simpler way... but I don't know if you are ready for it yet.

Do you have another problem like this?

Answer 20

I have nine more problems to do on a worksheet.

Answer 21

OK

Answer 22

I am going to try to do them by myself since I got you to help me I may have to ask you again later if that is okay?

Answer 23

Ooops.. Any algebraic Equation, which requires a solution should (must) have two sides, I mean exactly one "equals to (=)". Sorry. But this question is not complete.

Answer 24

Yes... I will stay on this post.

Answer 25

simplifying does not require an (=) sign. the results of simplifying do equal, but to simplify or reduce does not necessitate the need for an (=) sign :)

Answer 26

Okay. then it is 324*x^2*y. As I simplified (starting from the very first responce by blexting:
[{x^3}/{4y^2}] * [{1296y^4}/xy]

324{x^2}y

Answer 27

that would be a good result :) now all we need to know is if we have the right "problem" ;)

Answer 28

wpgaurav.. if you notice, Angelia said that the (2y)^4 was actually 2y^4 and (6y)^4 was actually 6y^4.... I wrote what I thought she was saying, but it wasn't.