consider f(x) = X^2+1 fill in the following table and approximate the instananeous rate of chnage of f as x approahces 2 from the left. lets use the number 1

Question

amistre64 · Answer

dy/dx = 2x..... so at x=1, the rate of change is 2

anonymous · Answer

Not sure exactly what it means by use the number 1?

amistre64 · Answer

er....-2  ;)

anonymous · Answer

Ok I agree with amistre

amistre64 · Answer

nahnahnah.....i got me peepers on backwards

anonymous · Answer

h=1

amistre64 · Answer

2....my vote is 2  lol

anonymous · Answer

Ok so basically the question wants the derivative at 2. So what amistre did was calculate the derivative of the function and then plugged 1 in for x, which equals 2.

anonymous · Answer

i may have forgotten to leave some info. he says 2, 2+5 should be used to solve the problem

anonymous · Answer

2,2+h i mean

amistre64 · Answer

2+5?  what...are we generating random functions now :)

anonymous · Answer

2,2+h i mean

amistre64 · Answer

you want to know the "limit" definition of the function as it approaches 2.... right?

anonymous · Answer

Ah that explains it

anonymous · Answer

yes this looks like a limit question

amistre64 · Answer

f(2+h) - f(2)
----------   something like that/
      h

amistre64 · Answer

(2+h)^2+1 - (2^2+1)
-------------------
             h

amistre64 · Answer

4 +8h + h^2 -4 -1
----------------
             h

anonymous · Answer

yes,
he skips some steps but here is what he has 
f(2+h)-f(2)
---------
h 
f(2+1)-f(2)
-------
1

amistre64 · Answer

make that 4h up there....

amistre64 · Answer

4h + h^2  -1
--------------
           h

amistre64 · Answer

al also dropped a "1" on the floor, but youlll find it :)

h(4+h)
------
    h


4+h


--------
    h

amistre64 · Answer

make h a 1?..that sounds odd..better relook at that

anonymous · Answer

there are 3 different h's
1, .1 and .01 and for this answer, the answer is five. after i do the others it is approaching 4

amistre64 · Answer

9 +1 - 4 - 1
----------  = 5 alrighty
        1

amistre64 · Answer

so you want x^2 + 1 at x = 2....

y' = 2x;  2(2) = 4

amistre64 · Answer

what your doing now is learning the "long" version that gives credence to the derivative..

anonymous · Answer

i think so. do you want me to put the problem in here exactly how i am looking at it?

amistre64 · Answer

nah, just filll out your tables and get your answer as 4 ;)