solve for x:
x/(x=3)+ 5/(x-7) =30/x^2-4x-21

Question

solve for x:
x/(x=3)+  5/(x-7) =30/x^2-4x-21

anonymous · Answer

Alright let's get them all to have the same denominator and you'll get :$$[x(x-7) + 5(x+3) -30]/(x-7)(x+3)$$

now let's simplify and do the calculation:
$$[x^2-7x +5x + 15 -30]/(x+3)(x-7)$$
$$(x^2-2x-15)/(x+3)(x-7)$$
$$(x+3)(x-5)/(x-7)(x+3)$$
(x-5)/(x-7)

hmm, I think you can take over from here :) good luck!

radar · Answer

I question the  x/(x=3) as shown in your original question.  I to will assume it was meant to be a +.  However the next equal sign I will take at face value and what you have is;$$x/(x+3)+5/(x-7)= 30/(x ^{2}-4x-21)$$

Note that the denominators of both fractions are equivalent and the two fractions are equal.
It can now be said the x+5 =30  x can be solved:  x=25