find a value of k so that the following equations are consistent:
kx - 3y - 5 = 0
8x + y - 17 =0
kx + 2y -10 = 0
can k have more than one value satisfying this condition?
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OpenStudy (amistre64):
kx = 3y+5
kx = -2y +10
OpenStudy (amistre64):
0 = 5y -5
5 = 5y
y = 1
OpenStudy (anonymous):
but what about the 2nd equation?
OpenStudy (amistre64):
kx = 8
k = 8/x when you find x :)
OpenStudy (amistre64):
8x +1 - 17 = 0
8x -16 = 0
8x = 16
x = 2
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OpenStudy (amistre64):
k = 4
OpenStudy (anonymous):
can't you just add all three equations together and solve for x in terms of k? I got x = 25/(2k+8)
OpenStudy (amistre64):
add? no, you would need to use one of them as a "control" and subtract the other 2 from it if you were going that route
OpenStudy (amistre64):
x + y = 0
2x + 3y = 0
3x +4y = 0 ??? nah
OpenStudy (anonymous):
okay that's what I confused myself on. thanks.
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OpenStudy (amistre64):
and since these are lines with different slopes, you cant have another value of "k" that would work.... thats just my gut feeling