how is factoring used to solve quadratic equations. Need to demonstrate the process with an example to show.
hi nikki
factoring is used every day
Hi
wazzup?
you asked the same question twice
Just having trouble with this class
ok
I know...for some reason, it happened
well if you throw a baseball with initial velocity v0, and initial height y0, you will need to factor to find when it hits the ground
huh?
the height of the ball is y = -1/2 gt^2 + vo*t + y0 , where g is your acceleration due to gravity (makes the ball come back to ground)
you wanna know about factoring right?
you asked where do we factor? when we solve trajectory problems you dummy
ask me huh again, i dare you
wow...that is mean
im not getting paid after all
amistre, super hero? wow
how is factoring used to solve quadratic equations. Need to demonstrate the process with an example to show. Is what I asked...I just do not understand what they want from me...
solving for any "roots" or "zeros" of an equation, what we are doing is finding all the places that the graph hits the x axis because y = 0 there.
amistre, its useless
he will just say "huh"
with quadratics, the line of the graph bends in such a manner that it can cross the x axis twis, so there may be at most 2 zeros to solve.
hmmm, i might have misread the question after all, my bad
amistre, can you solve the surface area of a torus, using integral 2pi y dS?
amistre, check the discriminant b^2 - 4ac, there are three cases
for example, can you see the place that this quadratic curve touches the x axis in two spots?
amistre, youre like god here. is youre mathematical knowledge proportionate to your score?
I appreciate all the help...I did not understand what they wanted...I'm sorry if it made anyone mad...
im just an idiot in disguise ;)
nikki, no one is mad :)
sometimes im mean, but im not mad :)
I am not a guy either...lol
oh sorry
wait, so youre a goddess :)
Its ok...sometimes I just do not get this stuff...I want to...it just does not happen...Not a math person...
amistre, surface area integrals. driving me nuts!!!
A mother of 2
when we factor the quadratic equation we get if "two" component parts that multiplied to get it: for example: x^2 +6x +8 is a quadratic expression right?
i think the student is lost in the math jargon. it happens
I think so
surface area integrals tend to be of the "ln(sec+tan)" variety right?
I HATE MATH!!!!!!!! Just sayin!
hmmm, not really , could be, check this link http://www.twiddla.com/521818 i posted the problem
nikki, you dont hate math. you just want things to be logical. i understand
Nikki: when we "factor" the quadratic we get this: (x+2)(x+4) = 0 we make it equal to zero because we want to know what x is when y = 0
cantor; ill check it out in abit ;)
thanks
nikki, whats a quadratic equation> what it means to "solve quadratic equation"
Oh yes...logical would be great:) I am one that needs to get it right now, I am a perfectionist and this is not helping anything, throws me off...very frustrating!
ok , slow down. ok lets get the jargon straight
a quadratic equation is generally y = ax^2 + bx + c
ill show how factoring helps later to solve, but what does it mean to solve a quadratic equation. this is more jargon or math lingo
Nikki: we know that any number when multiplied by "0" = 0 right? for example: 3(0) = 0 34(0) = 0 r2d2(0)= 0 you with me?
sure...
amistre, want to chime in. what it means to "solve quadratic equation"
cantor, to find their roots :)
ok
the roots are the x solutions such that ax^2 + bx + c = 0
Nikki; then when we have the factored form of a quadratic, we know that one or the other has to equal zero in order for function to equal zero. tell me: (x+4)(0) = 0 ? does (0)(x+2) = 0?
ok, i got lost there for a second. ok a quadratic equation in x is ax^2 + bx + c = some number, correct? a quadratic function i think would be y = ax^2 + bx + c , because now you have y is a function of x
ok...I think I got it....hopefully:) Thanks for all your help!
amistre, ill politely bow out of here, but please check my twiddla
ill be there shortly, and maybe I can even be helpful ;)
oh i didnt state the question, one sec
surface area of a torus. it is generated by circle with radius r , off center. Suppose the circle is centered at (x - R)^2 + y^2 = r^2, and R> r. so the distance from (0,0) to the center of the circle is (R,0) which has radius r. Ok the integral i got is int 2pi y sqrt [ 1+ (dy/dx)^2] = int 2pi sqrt ( r^2 - ( x-R)^2) [ 1 + (-2(x-R)/(2sqrt( r^2 - ( x-R)^2) ^2 ]
Is this to me?
Nikki; the factored form allows us to "see" into the quadratic, and know quite easily what the solutions are. (x+4)(x+2) = 0 x = -4 or x = -2 because both these solutions makes one or the other a (0) right?
yeah
ack!!...a torus surface..... lol
Nikki: then that is all ther eis to it, I just hope you can make sense of it between the posting lol
I am so confused...not sure if it was all for me or for you guys?lol
well i have two ways to solve it, one way works, the other doesnt, int 2pi y ( 1 + dy/dx^2) dx , that doesnt work, but int 2pi x ( 1 + dx/dy^2) dy that works. not sure why
nikki, ok i will start over , want to do this? ARE YOU READY!!!
YES! Sorry...
oh no im gonna miss jay leno
ok , uno momento
I am glad I have DVR
what do you watch?
a lot of shows, I really like greys and things like that...so I record them so I do not have to watch all the commercials
I see the equations..... wheres the torus?
ok whats a quadratic equation In mathematics, a quadratic equation is a polynomial equation of the second degree. The general form is ax^2 + bx + c = 0
cantorset, i wrote log3(n)<n as n<3^n for the log proof sorry for interrupting later
Are you still there?
hey sorry
Its ok....I have to figure out an example for this, and I guess I am not getting this as much as I wanted to be or thought...
give me 5 minutes
ok....I appreciate your help...I really do.
I will go check on my daughters
ok I'm back.....
welcome back :)
Thanks! I am trying to figure out how some get this math stuff, and then there is me...who has no idea and thinks I get it and then does not...
Join our real-time social learning platform and learn together with your friends!