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So, CALCULUS 1 question, if i have: Lim e^-1/(x+1) = 0 x->-1^+ Lim e^-1/(x+1) = infinite x->-1^- can i say this is an Vertical assimptote?
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x->a, f(x)->infinity then it is a vertical asymp. x->a+,f(x)->infinity then is is a vertical asymp. x->a-,f(x)->infinity then it is a vetical asymp.
I know but, my problem is, even though -1+ is going to 0 I can say that its a vertical asymptote since -1- is going to infinite?
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