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OpenStudy (anonymous):
solve y'=x+y using the substitution of u=x+y?
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OpenStudy (anonymous):
y'=u What more do you need solves? Are we integrating this or what?
OpenStudy (anonymous):
the answer is y=Ke^x - x - 1 ??????????
OpenStudy (anonymous):
No. It looks like y' = x + y is implicit differentiation.
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