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Mathematics 19 Online
OpenStudy (anonymous):

solve y'=x+y using the substitution of u=x+y?

OpenStudy (anonymous):

y'=u What more do you need solves? Are we integrating this or what?

OpenStudy (anonymous):

the answer is y=Ke^x - x - 1 ??????????

OpenStudy (anonymous):

No. It looks like y' = x + y is implicit differentiation.

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