calculate the gradient
\[f(x,y)=\sqrt{36x ^{2}+ 4 y ^{2}}\]
\[\Delta\f] =? triangle is supposed to be inverted
\[\Delta f(x,y) =?\]
diff. f w.r.t. x keeping y as constant Fx= [1/ 2 sqrt(36x^2 + 4y^2) } *72x similarly, diff f w.r.t. y keeping x as constant Fy= [1/ 2sqrt (36x^2 + 4y^2) } * 8y combining these gives us our gradient vector
and u might have used wrong symbol for gradient ..its inverse triangle
yes. i got tht. answer confirmed =) yes i had mentioned it above tht there should ve been inverted triangle
pls fan me ..to keep the help sharing
ok but b4 that. an imp question.
sure
u know directional derivative completely? and Lagrange multiplier too?
i know the first one..havent touched the latter one yet..
oh.
?
well the question was requiring Lagrange multiplier
:(
so what do i need to do to get ur vote? hahha
=D answer my next question if needed =P
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