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Mathematics 18 Online
OpenStudy (anonymous):

calculate the gradient

OpenStudy (anonymous):

\[f(x,y)=\sqrt{36x ^{2}+ 4 y ^{2}}\]

OpenStudy (anonymous):

\[\Delta\f] =? triangle is supposed to be inverted

OpenStudy (anonymous):

\[\Delta f(x,y) =?\]

OpenStudy (anonymous):

diff. f w.r.t. x keeping y as constant Fx= [1/ 2 sqrt(36x^2 + 4y^2) } *72x similarly, diff f w.r.t. y keeping x as constant Fy= [1/ 2sqrt (36x^2 + 4y^2) } * 8y combining these gives us our gradient vector

OpenStudy (anonymous):

and u might have used wrong symbol for gradient ..its inverse triangle

OpenStudy (anonymous):

yes. i got tht. answer confirmed =) yes i had mentioned it above tht there should ve been inverted triangle

OpenStudy (anonymous):

pls fan me ..to keep the help sharing

OpenStudy (anonymous):

ok but b4 that. an imp question.

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

u know directional derivative completely? and Lagrange multiplier too?

OpenStudy (anonymous):

i know the first one..havent touched the latter one yet..

OpenStudy (anonymous):

oh.

OpenStudy (anonymous):

?

OpenStudy (anonymous):

well the question was requiring Lagrange multiplier

OpenStudy (anonymous):

:(

OpenStudy (anonymous):

so what do i need to do to get ur vote? hahha

OpenStudy (anonymous):

=D answer my next question if needed =P

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