Question

how to sketch 1+ [2/(x+1)]

Answer 1

u mean a graph?

Answer 2

r u der?

Answer 3

yes a graph

Answer 4

alright, lets take the given function as y

so, y=1+[2/(x+1)]

Answer 5

now, substitute x=0, u'll get y value, so this gives u one point on the graph like (x,y)

i think u know how to plot point on a graph , right?

Answer 6

yes

Answer 7

thank you very much lokisan ^.^

Answer 8

you still need to do what thinker was doing...i.e. drawing it yourself

Answer 9

and yeah...try plugging more point..x=-1,1, -2,2,....so on..to get a good graph :)

Answer 10

sry *points

Answer 11

and the graph that u get finally is a symmetric one, i.e. symmetric about the 1st & 3rd quadrants

Answer 12

This one shows both asymptotes.

Answer 13

thank you very much thinker!
=]

Answer 14

You should notice some qualitative aspects of the function to make your drawing easier. For example, as x approaches -1, the function approach plus or minus infinity, depending on which direction -1 is being approached.

As x goes to plus or minus infinity, the function goes to 1.

Answer 15

ur welcome @virtus :)

Answer 16

i'm a bit confused on the asymptotes bit i know we can determine one asymptote by looking at the denominator of the fraction but how did you get the other, y =1

Answer 17

Once you get a bit more advanced, you'll notice that your function is just a composition of functions and that what you've got is just a hyperbolic function (1/x) that has been translated by a horizontal shift (i.e. x goes to x+constant)) with the result of that multiplied by 2 (thereby pushing the corner of the hyperbola further out) and then the entire thing shifted up 1 unit.

Answer 18

\[y=1+\frac{2}{x+1}\]What happens as x gets larger without bound?

Answer 19

Very large positive x will make 2/(x+1) a very small positive number.
Very large negative x will make 2/(x+1) a very small negative number.

You'll be adding/subtracting very small amounts for large x. As x gets large, this effect is more pronounced.

Answer 20

So basically, the function approaches the value 1 and x approached plus or minus infinity.

Answer 21

You can see that in the plot.

Answer 22

Btw, the software I used to make that plot is free:

http://www.geogebra.org/cms/

Answer 23

got it @virtus?

Answer 24

oh well, we'll assume virtus has got it... :p

Answer 25

hahahhas sorry for late reply
THANK YOU SO SO MUCH!

Answer 26

np

Answer 27

ur wc

Answer 28

Use wolframalpha
http://www.wolframalpha.com

just write your formula and hit Enter