Question

solve by substitution.
x/3 + y/2 = 4
x/2 - y = -1

Answer 1

please help guys ! =(

Answer 2

First get y by itself in bottom equation
-> y = 1+x/2
Then replace this for y in top equation
->x/3 + (1+x/2)/2 = 4
solve for x by combining fractions using common denominators...

Answer 3

and can you help me with the combining fractions part?

Answer 4

1+x/2 needs denominator of 2
-> 2/2 + x/2 = (x+2)/2

Answer 5

(x+2)/2 * 1/2 = (x+2)/4
with me?

Answer 6

yes, now what?

Answer 7

Then x/3 + (x+2)/4 = 4
to add these we need denominator of 12
->(x/3)*(4/4) + (x+2)/4*(3/3)
= 4x/12 + 3(x+2)/12
= (4x + 3x + 6)/12

Answer 8

(7x+6)/12 = 4
multiply by 12 on both sides
->7x + 6 = 48
x = 6

Answer 9

did you follow that?

Answer 10

yes thank you so much. now how do i figure out y?

Answer 11

plug in 6 for x into that equation above
remember whn we solved for y initially
->y = 1+x/2
replace x with 6
->y = 1+(6/2) = 1+3=4