Question

solve: 3^(2x +1) = 70

Answer 1

let me write it out for you.. give me amin

Answer 2

\[3^{2x+1} = 70\]
\[\log 3^{2x+1} = \log 70\]
\[(2x+1) \log3 = \log70\]
\[2x = (\log70/\log3) -1\]
x =( log70/log3 - 1) /2

Answer 3

then just put that into ur calculator and voila :)

Answer 4

app 1.43

Answer 5

is there a way it can be done without logs?