Question

rationalize denominator : please help
1.) 4/ sqrt. 7p
2.) srqt.98/x
3.) 9/3 sqrt.y
4.) sqrt.7 / sqrt.5 +7

Answer 1

1.)
4/7p−−√

2.)
98−−√/x

3.)
9/3y√

4.)
7√/5√+7

Answer 2

\[1.) 4/\sqrt{7p}\]

Answer 3

2.) \[\sqrt{98}/x\]

Answer 4

The denominator is not supposed to have a square root. So when you rationalize you get rid of the square root in the denominator by multiplying the numerator and denominator by the square root, which is essentially multiplying by 1 so it doesnt change the value of the expression.

Answer 5

3.) \[9/^{3}\sqrt{y}\]

Answer 6

4.) \[\sqrt{7} / \sqrt{5} + 7\]

Answer 7

haha thats why its a cubed root, not 9/3

Answer 8

yes i sent you the correction in the other post

Answer 9

xavier : so i take out the sqrt ?

Answer 10

LIke for 4/sqrt(7p). Multiply the numerator and denominator by sqrt(7p). So the denominator gets "rationalized" because sqrt(7p)*sqrt(7p) is simply 7p.

Answer 11

so the answer would be : 4 sqr.7p ? or 4sqrt.7p/7p ?

Answer 12

or ?

Answer 13

4sqrt(7p)/7p

Answer 14

and fot the second one ? would it be 7sqrt.2x ? or 7sqrt. 2/x ?

Answer 15

\[7 \sqrt{2x} , 7 \sqrt{2/x}\]