confused on this one because if i multiply the first equation by 2, it cancels out both the x and y components. Solve by the elimination method. 2x + 3y =1 4x + 6y = 2
that is okay but you need to multiply first equation by -2
sorry about that...you will get 0=0 which is always true so infinitely many or all real numbers as solution
ok, that is the first time i saw the answer come out like that, thanks!
you're welcome....good job on elimination...you may also get something like -2=0 which is never true so NO SOLUTION
so which would it be, infinitely many solutions or no solution?
no solution is a different type-when left side doesn't equal right side INFINETLY MANY/ALL real numbers mean same things
You have what is known as an identity.
exactly radar
I hope the course that ms elegant prepared for such an event lol
can you help me with polynomial question Find polynomial P(n)=Sn for 1, 2, 3, ...10 and explain method
so the answer i get when multiplying by -2 is 0=-2. so I'm guessing that the answer is there is no solution. but how do i perform a check to make sure that my answer is right?
It is unsolvable,it is an identity, it is the same equation just one is double the other you need two distinct equations for the two unknowns.
btm2011, I wouldn't be much help on that polymonial series!
ok, so there is no solution, thx!
Ms elegant do you understand even though they provided you with two equations, they are actually the same, one does not provide any new information for you.
for that problem the answer is all real numbers, infinitely many (identity) because 0=0 -2(2x+3y=1)____-4y-6y=-2
-4y-6y=-2 + 4x+6y=2
There is a solution!
ok i think i got it, there is a solution, but it is just an infinite amount of solutions that can be the answer, right?
YES...bc every number equals itself
yes, x=0 and y=1/3 could be a solution, but there is no specific solution, I could put down another solution like x=-2, y=1
ok, i get it. and that's the check, that several answers fit this equation - so there are infinite solutions, not just one
That is what it seems to be.
ok great thx! i appreciate the explanation so that i could understand what i was doing
GREAT!
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