can anyone solve these problems???
M,A,M,J,J,A,S,O,..........What comes next?
a.N b.M c.A d.P
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OpenStudy (anonymous):
sathi, you posted a wrong problem, whats wrong with you,
OpenStudy (anonymous):
the sequence is 3, 7, 31, 211
OpenStudy (anonymous):
NOT 3, 7, 32, 211,
OpenStudy (anonymous):
so how did u prove that 3 , 7 31, 211
OpenStudy (anonymous):
but the question was same in the exam paper.
31 not 32
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OpenStudy (anonymous):
but anyway how did u solve that ..
OpenStudy (anonymous):
you posted 32 , scroll to your question
OpenStudy (anonymous):
look at the problem you posted earlier you will find 32
OpenStudy (anonymous):
oh... i mean 32 not 31
OpenStudy (anonymous):
whats ur process
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OpenStudy (anonymous):
no, wait, admit that you posted an incorrect problem
OpenStudy (anonymous):
ok...
OpenStudy (anonymous):
look at the post , on the left, scroll down
OpenStudy (anonymous):
follow me , one sec
OpenStudy (anonymous):
wow i got answer
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OpenStudy (anonymous):
ok so the sequence 3, 7, 31, 211, is
1 + 2, 1 + 2 * 3 , 1 + 2 * 3 * 5 , 1 + 2*3*5*7
OpenStudy (anonymous):
its option no.A...N
OpenStudy (anonymous):
wait, lets do the sequence
OpenStudy (anonymous):
what is special about 2,3,5,7
OpenStudy (anonymous):
they are primes
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OpenStudy (anonymous):
so the next number will be 1 + 2*3*5*7*11 = 2311
OpenStudy (anonymous):
2311, 30031, 510511
OpenStudy (anonymous):
yea i agree with ur idea...thanks
OpenStudy (anonymous):
how did you solve your MAMJAN problem?
OpenStudy (anonymous):
its the series of month starting from M(march)
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OpenStudy (anonymous):
is that a code, letters mean numbers
OpenStudy (anonymous):
haha
OpenStudy (anonymous):
nice one
OpenStudy (anonymous):
X % of Y is Y % of :
a.x b.y/100 c.x/100 d.100x
OpenStudy (anonymous):
wait, this is an open question, the sequence before are called euclid numbers
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OpenStudy (anonymous):
are there an an infinite number of prime euclid numbers, E6 is not prime for example
OpenStudy (anonymous):
hey man m the student of medicine so i dont know the mathmatical calculation much more......so would u plz describe in simple way.
OpenStudy (anonymous):
my guess was a x
OpenStudy (anonymous):
yes a
OpenStudy (anonymous):
x is correct
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OpenStudy (anonymous):
but its c in book
OpenStudy (anonymous):
x% of y = x/ 100 * y = x * y/100 = y% of x
OpenStudy (anonymous):
oh , hmmmm
OpenStudy (anonymous):
well another question.
OpenStudy (anonymous):
in a class with a certain number of students , if one student weighing 50kg is added then average weight of class incereases by 1 kg ,if one more student weighin 50kg is added then the average weight of class increasses by 1.5kg over the original average? what isthe original average weight (in kg) of the class?