Question

I need some help.. I've already done these problems and i got them back and they need fixed.. will someone please help me

Answer 1

find the surface area of the solids. the pyramids are regular and the prisms, cylinders, and cones are right

Answer 2

For the first one, you can find the surface area of the cylinder part ( the part that looks like a can) by using 2(pi)r * height

Answer 3

Then add the area of the bottom circle (pi)r^2

Answer 4

and then add SA of the cone, pi*r*s
s is the slant height

Answer 5

thats what i did and i got 211.95cmin^2

Answer 6

ok, let me try and work it out with the numbers, just a sec

Answer 7

Do you know the right answer?

Answer 8

no

Answer 9

I got 203.47cm^2

Answer 10

wekkm 203.58 cm^2 when I use the pi button

Answer 11

oops, I mean "well"

Answer 12

for the cylinder, it's 30.6pi, the circle base is 9pi, and the cone is 25.2pi

Answer 13

so it would be 30.6pi+9pi+25.2pi

Answer 14

yes, and with that I got 64.8pi

Answer 15

For the 2nd picture, there are 6 sides that are rectangles, so that would be 6(base*height).
I can't tell in the picture, is the height of each triangle 5, or what does the 5 go to?

Answer 16

to the slant eight of the triangle

Answer 17

height*

Answer 18

6 there are 6 triangles, each with a base of 3 and slant height of 5.....that would be 6 * 1/2 (base * height)

Answer 19

So, 6(3*6) +6(1/2)(3*5)

Answer 20

and then would you have to add the area of the base?

Answer 21

855+64.8pi

Answer 22

where did you get 855?

Answer 23

6(3*6) +6(1/2)(3*5)

Answer 24

6(3*12) +6(1/2)(3*5)
that would be a 12 in the first ( )

Answer 25

153

Answer 26

64.8pi went to the first drawing...the one above is for the 2nd picture

Answer 27

I get 261 in^2

Answer 28

i thought the first pic was 203.58cm^2

Answer 29

yes, that's what I got....it was 64.8pi, which = 203.58cm^2

Answer 30

ok

Answer 31

for the 2nd drawing I get 261in^2 + area of that hexagon base

Answer 32

261 in^2 so this is the second pic surface area?

Answer 33

yes, but I dont' know how to find area of the base

Answer 34

will u help me with some other ones that ive already done i just got them wrong

Answer 35

i will try

Answer 36

okay.. for this one i needed to find the value of x.. and i got 3

Answer 37

v=1/3 pi r^2 h

Answer 38

I get 3 also

Answer 39

so redoing it i get \[56.5=1/3\times \pi \times x ^{2}\times6\]

Answer 40

3 meters

Answer 41

\[56.5=6.28x ^{2}\]

Answer 42

yes, i get that too

Answer 43

Did it count off because you didn't put meters?

Answer 44

maybe

Answer 45

oh, wait, is x the diameter? We only found the radius.

Answer 46

so x = 6 meters

Answer 47

56.5/6.28=8.996

Answer 48

yeah, then sq rt of that gives the radius of that circle as 3 meters

Answer 49

but in the drawing, the x represents the diameter, which would be twice the radius, or 6 meters

Answer 50

I've got to go....good luck!

Answer 51

thank u

Answer 52

you're welcome