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Mathematics 13 Online
OpenStudy (anonymous):

find the absolute and local maximum and minimum values of f.f(x) = 8 - 2x x ≥ 1

OpenStudy (anonymous):

Is this calculus? Or algebra 2?

OpenStudy (anonymous):

Find all critical points and plug them in to the function and the highest number is the absolute max and lowest is the absolute min. Dont forget to include 1 since that's one bound.

OpenStudy (anonymous):

how do i find the criteria

OpenStudy (anonymous):

Are you taking algebra, or calculus?

OpenStudy (anonymous):

Because there are a few ways to do this depending on what you know.

OpenStudy (anonymous):

calculus

OpenStudy (anonymous):

Ok, so take the derivative of f. What do you have?

OpenStudy (anonymous):

-2

OpenStudy (anonymous):

Right. So when you are finding local mins/maxes you are looking for places where the derivative is 0. When is -2=0?

OpenStudy (anonymous):

never lol

OpenStudy (anonymous):

So there are no local mins or maxes. So you just have to look at the value at the "end" points for absolute mins/maxes. Which is to say x=1, there is no other end point because the other bound goes to \(\infty\)

OpenStudy (anonymous):

So what is the value at x=1?

OpenStudy (anonymous):

6

OpenStudy (anonymous):

And what happens as x gets larger? Is f(1)=6 an absolute min or is it a max?

OpenStudy (anonymous):

max

OpenStudy (anonymous):

so 6 is the max

OpenStudy (anonymous):

Yes. And it has no absolute min, and no local mins or maxes.

OpenStudy (anonymous):

ok i get it!!!

OpenStudy (anonymous):

thank u!

OpenStudy (anonymous):

Of course!

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