find the absolute and local maximum and minimum values of f.f(x) = 8 - 2x
x ≥ 1
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OpenStudy (anonymous):
Is this calculus? Or algebra 2?
OpenStudy (anonymous):
Find all critical points and plug them in to the function and the highest number is the absolute max and lowest is the absolute min.
Dont forget to include 1 since that's one bound.
OpenStudy (anonymous):
how do i find the criteria
OpenStudy (anonymous):
Are you taking algebra, or calculus?
OpenStudy (anonymous):
Because there are a few ways to do this depending on what you know.
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OpenStudy (anonymous):
calculus
OpenStudy (anonymous):
Ok, so take the derivative of f. What do you have?
OpenStudy (anonymous):
-2
OpenStudy (anonymous):
Right. So when you are finding local mins/maxes you are looking for places where the derivative is 0. When is -2=0?
OpenStudy (anonymous):
never lol
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OpenStudy (anonymous):
So there are no local mins or maxes. So you just have to look at the value at the "end" points for absolute mins/maxes. Which is to say x=1, there is no other end point because the other bound goes to \(\infty\)
OpenStudy (anonymous):
So what is the value at x=1?
OpenStudy (anonymous):
6
OpenStudy (anonymous):
And what happens as x gets larger? Is f(1)=6 an absolute min or is it a max?
OpenStudy (anonymous):
max
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OpenStudy (anonymous):
so 6 is the max
OpenStudy (anonymous):
Yes. And it has no absolute min, and no local mins or maxes.