Question

Of this quadratic equation, does a=-2, b=3, and c=-4?

Answer 1

\[-2y ^{2}+3y=-4\]

Answer 2

c = 4

Answer 3

thanks!makes that become positive?

Answer 4

-2y^2 + 3y +4 =0

Answer 5

and would you mind if I try and solve it and post it on here so you can let me know if the answer I get is correct? :)

Answer 6

ok

Answer 7

\[-3 + or - \sqrt{41} \over -4\] is this my answer or is there more I can do with it? Also, would there be 2 real answers?

Answer 8

or 2 non real solutions since there are negative numbers..

Answer 9

D = b^2-4ac = 9-(4*-2*4) =9+32 = 41 >0 means 2 real answer
u are correct

Answer 10

okk thanks. I'm kind of confused though. Would the 2 answers be what I put? If so, wouldn't they not be real since there are negative numbers? Sorry. I guess to clarify could you post what the final 2 answers are? :)

Answer 11

(-3 - sqrt(41))/-4 and (-3 + sqrt(41))/-4
not real or imaginary is if sqrt(-41)
- sqrt(41) is real because negative sign is out of sqrt

Answer 12

oohh ok. thanks!

Answer 13

no problem