Question

for this quadratic equation, does a=6,b=-3, and c=-2?

Answer 1

\[6x ^{2}-3=-2x\]

Answer 2

no....b=2, c=-3

Answer 3

Or should b or c be positive?

Answer 4

once you put everything together on one side, you get: 6x^2+2x-3=0

Answer 5

6x^2+2x-3, a=6 b=2 c=-3

Answer 6

ohh because it has x with it?

Answer 7

exactly :)

Answer 8

think of the generic form of polynomials like that: ax^2+bx+c

Answer 9

thanks! I'm going to try and solve it, would you mind checking it to see if I have the correct answer? :)

Answer 10

yup

Answer 11

\[4+ or - \sqrt{76}\over 12\] not sure if this can be simplified or not

Answer 12

D = 4+72 = 76 > 0 --> 2 real number
(-2 +- sqrt(76)) 4

Answer 13

yup ur rite sorry im typo, denominator is 12

Answer 14

that should be a -2, not a 4. remember the formula is [-b +/- sqrt(b^2-4ac)]/2a

Answer 15

ohh ok, it is -2 instead of 4 though?

Answer 16

what is b in this equation? its 2...so-b is -2

Answer 17

in the original equation it is -2..but does it turn to positive 2 when we solve it?

Answer 18

in the original is 2, coz its -b so it's -2

Answer 19

ohhhh right. My mistake. thanks for clarifying!

Answer 20

:)

Answer 21

wait a sec..i tried to submit the answer and it says it's not in simplest form?

Answer 22

76=4x19. You can pull out a 2 there and then factor a 2 from the whole numerator and then you end up with: [-1+/-sqrt19]/6

Answer 23

Thanks!