Use the quadratic formula to find the roots of the equation. Round to tenths if necessary. x2 + x +10 = 0

A. {3.2}
B. {-5.5, -2}
C. {-3.2, 3.2}
D. no real number solution

Question

Use the quadratic formula to find the roots of the equation. Round to tenths if necessary. x2 + x +10 = 0

A. {3.2}
B. {-5.5, -2}
C. {-3.2, 3.2}
D. no real number solution

anonymous · Answer

well, this is very easy if you know the quadratic formula

anonymous · Answer

$$-b \pm \sqrt{b^2-4ac}/2a$$

anonymous · Answer

this is D.  BECAUSE DISCRIMINANT IS LESS THAN ZERO

anonymous · Answer

ohhhhhhh ok ok ok. Thx (: :D

anonymous · Answer

Dawn, do you know what he means by discriminant?

anonymous · Answer

no i dont know what that means ;(

amistre64 · Answer

discrimination is a term used in racism alot; it means to choose between options based on certain conditions.  In racism, that condition was skin color.  In math that condition is the sign of the number under the square root radical

anonymous · Answer

haha wow. Relating it to real world rly helps to unerstand it even better.. wow thanks!! :D

amistre64 · Answer

:)

square roots have 3 conditions:

a negative number is bad, or just means that the solutions are imaginary.  When it asks for "real" roots it wants a number eqal to or greater than zero.

when the value is zero, then that part of the formula goes to zero and we are left with the other side only.   any number + 0 = itself.  any umber - 0 = itself.... so there is only one solution to the discrimnate being 0....

if it is a positive value, then we have 2 solutions for our quadratic because it tells us that the other part is added and subtracted by the same amount....

amistre64 · Answer

<.....-8..........-3............2.........>
             -|5|        +|5|

anonymous · Answer

ohhhh ok .

amistre64 · Answer

our roots in that last case are -8 and 2... becasue they are the same distance from  the (-3)

amistre64 · Answer

when the distance is zero.....we only have the -3 left on the board to play with...

<...................-3.......................>
             -|0|        +|0|

amistre64 · Answer

there is no real number that is a negative distance; so that would actually cause a rip in the timeline and suck the -3 right out into another diminsion and wed be left with nothing to play with.

<....................................>
              sqrt(-#)

amistre64 · Answer

that other diminsion is up or down in this case :)  in either case, the -3 was removed from the timline itself and out of reach......