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Mathematics 21 Online
OpenStudy (anonymous):

16 = 1/2*4 (3+ b2)

OpenStudy (anonymous):

\[16 = half * 4* (3 + b _{2})\]

OpenStudy (shadowfiend):

Are you trying to solve for \(b_2\)?

OpenStudy (anonymous):

yes.

OpenStudy (shadowfiend):

Ok, so let's start at the top. When you have a multiplication between regular numbers, go ahead and do that first. In this case: \[16 = \frac{1}{2}4(3 + b_2)\] You can do the multiplication of 1/2 * 4. What do you get?

OpenStudy (anonymous):

2?

OpenStudy (shadowfiend):

Right. So then we have: \[16 = 2(3 + b_2)\]

OpenStudy (shadowfiend):

Now the easiest thing now is to move that 2 over to the left. Can you do that?

OpenStudy (anonymous):

yes....16 -2 = 14

OpenStudy (shadowfiend):

Not quite. 2 is multiplied on the right, so you have to divide, not subtract, to get it back.

OpenStudy (shadowfiend):

Or, to move it over, rather.

OpenStudy (anonymous):

yes.... duh..I realized that shortly after posting...

OpenStudy (anonymous):

so 16/2 is 8 right?

OpenStudy (shadowfiend):

Right. So now we have: \[8 = 3 + b_2\]

OpenStudy (anonymous):

divide 8 by 3 now?

OpenStudy (shadowfiend):

No, 3 is added in, so we subtract it this time :)

OpenStudy (shadowfiend):

Remember, we can also rewrite that: \[8 = b_2 - 3\]

OpenStudy (shadowfiend):

!! Sorry, I meant: \[ 8 = b_2 + 3 \]

OpenStudy (anonymous):

okay...so \[b _{2}\] =5?

OpenStudy (shadowfiend):

Right! (Sorry for the delay.)

OpenStudy (anonymous):

no biggie

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