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OpenStudy (anonymous):
\[16 = half * 4* (3 + b _{2})\]
OpenStudy (shadowfiend):
Are you trying to solve for \(b_2\)?
OpenStudy (anonymous):
yes.
OpenStudy (shadowfiend):
Ok, so let's start at the top. When you have a multiplication between regular numbers, go ahead and do that first. In this case:
\[16 = \frac{1}{2}4(3 + b_2)\]
You can do the multiplication of 1/2 * 4. What do you get?
OpenStudy (anonymous):
2?
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OpenStudy (shadowfiend):
Right. So then we have:
\[16 = 2(3 + b_2)\]
OpenStudy (shadowfiend):
Now the easiest thing now is to move that 2 over to the left. Can you do that?
OpenStudy (anonymous):
yes....16 -2 = 14
OpenStudy (shadowfiend):
Not quite. 2 is multiplied on the right, so you have to divide, not subtract, to get it back.
OpenStudy (shadowfiend):
Or, to move it over, rather.
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OpenStudy (anonymous):
yes.... duh..I realized that shortly after posting...
OpenStudy (anonymous):
so 16/2 is 8 right?
OpenStudy (shadowfiend):
Right. So now we have:
\[8 = 3 + b_2\]
OpenStudy (anonymous):
divide 8 by 3 now?
OpenStudy (shadowfiend):
No, 3 is added in, so we subtract it this time :)
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OpenStudy (shadowfiend):
Remember, we can also rewrite that:
\[8 = b_2 - 3\]