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Mathematics 13 Online
OpenStudy (anonymous):

Find the surface area

OpenStudy (anonymous):

OpenStudy (anonymous):

and this

OpenStudy (dumbcow):

hello for the first one you need to use formula for SA of sphere and then plug in the radius so what is SA of a sphere? what is the radius of our sphere?

OpenStudy (anonymous):

so i have to divide 1.8 by 2

OpenStudy (dumbcow):

correct because radius is half the diameter

OpenStudy (anonymous):

i got 0.9

OpenStudy (dumbcow):

now substitute that in for r in SA formula

OpenStudy (anonymous):

ok i am doing it right now

OpenStudy (anonymous):

i did the volume then i got 0.972pi

OpenStudy (dumbcow):

correct for volume i thought we were doing surface area

OpenStudy (anonymous):

yea but my homework say to find both of them

OpenStudy (dumbcow):

oh ok what would SA be then

OpenStudy (anonymous):

3.24pi

OpenStudy (dumbcow):

good job for next one do the same thing except at the end we will divide by 2 because its only half a sphere

OpenStudy (anonymous):

what do you mean?

OpenStudy (dumbcow):

it shows image of half sphere with radius of 12 right? so find volume and SA using same formulas substituting 12 for r but we only want half the volume and half the SA

OpenStudy (anonymous):

i find the volume is 1152pi

OpenStudy (dumbcow):

correct

OpenStudy (anonymous):

SA is 432pi right?

OpenStudy (dumbcow):

no i get 288pi SA = 4pi*12^2 = 4pi*144 = 576pi take half of 576 288

OpenStudy (anonymous):

ok thank here the another question: The shaded circle at right has area 40π cm2. Find the surface area of the sphere.

OpenStudy (dumbcow):

i dont understand how are the circle and sphere related?

OpenStudy (anonymous):

here the hint:The surface area of a sphere is how many times the area of a circle with the same radius?

OpenStudy (dumbcow):

ok so they share the same radius is the entire circle shaded?

OpenStudy (anonymous):

here the picture

OpenStudy (dumbcow):

ok thanks use area of circle formula to find radius, then plug that into SA formula A = pi*r^2 = 40pi

OpenStudy (anonymous):

i have to divide pi in both side

OpenStudy (dumbcow):

yes

OpenStudy (anonymous):

i find the raidus 6.32455532

OpenStudy (dumbcow):

correct

OpenStudy (dumbcow):

SA=4pi*(6.32)^2

OpenStudy (anonymous):

159.7pi

OpenStudy (dumbcow):

correct and you can round up to 160 since we rounded the radius

OpenStudy (anonymous):

Find the volume of a sphere whose surface area is 64π cm2.

OpenStudy (dumbcow):

first find radius 4pi*r^2 = 64pi

OpenStudy (anonymous):

4

OpenStudy (dumbcow):

good now use that to find volume V = 4/3pi*r^3

OpenStudy (anonymous):

i got 256pi over 3

OpenStudy (dumbcow):

correct

OpenStudy (anonymous):

Find the surface area of a sphere whose volume is 288π cm3.

OpenStudy (dumbcow):

same thing we just did except use volume formula to find radius V = 4/3pi*r^3 = 288pi

OpenStudy (anonymous):

what should i do with 4/3 pi?

OpenStudy (dumbcow):

well first get rid of pi by dividing pi on both sides like last time then we will divide by 4/3

OpenStudy (anonymous):

x by 3/4 by both side

OpenStudy (dumbcow):

correct

OpenStudy (anonymous):

what about 288*3/4

OpenStudy (dumbcow):

think of it as (288*3)/4

OpenStudy (anonymous):

i got 6 as radius

OpenStudy (dumbcow):

correct put that in SA formula

OpenStudy (anonymous):

144pi

OpenStudy (dumbcow):

correct

OpenStudy (anonymous):

if the radius of the base of a hemisphere (which is bounded by a great circle) is r, what is the area of the great circle? What is the total surface area of the hemisphere, including the base? How do they compare?

OpenStudy (anonymous):

OpenStudy (dumbcow):

you can do this one, its just using the formula for circle area and SA the radius is just r

OpenStudy (anonymous):

ok i will but i need to leave right but i tell you when i get home

OpenStudy (dumbcow):

k

OpenStudy (anonymous):

ok i'm back so my homewprk paper has Agreat cicrle=,Shemisphere= and SA Hemisphere=__xA of great circle

OpenStudy (dumbcow):

yes lets fill in the gaps A = area circle SA = area circle + 1/2 SA of sphere

OpenStudy (anonymous):

the area of that is pir^2

OpenStudy (dumbcow):

good A = pir^2

OpenStudy (anonymous):

we know the radius is r so that mean..

OpenStudy (dumbcow):

whats SA of sphere

OpenStudy (anonymous):

4pir^2

OpenStudy (dumbcow):

good SA hemishere = pir^2 +(1/2)*4pir^2 add like terms

OpenStudy (anonymous):

3pir^2

OpenStudy (dumbcow):

good and A = pir^2 right? so SA = ___ * A

OpenStudy (anonymous):

what the of Agreat cicrle= and Shemisphere=

OpenStudy (anonymous):

i forgot to put answer

OpenStudy (dumbcow):

A = pir^2 SA hemishere = pir^2 +(1/2)*4pir^2 add like terms

OpenStudy (anonymous):

so that is the answer or i have to solve it

OpenStudy (dumbcow):

no thats the answer, remember we dont know what r is

OpenStudy (anonymous):

oh ok so SA = r * A

OpenStudy (dumbcow):

well does that sense? sub in what we know SA = 3pir^2 and A=pir^2 3pir^2 = r*pir^2 is that true?

OpenStudy (anonymous):

not really

OpenStudy (dumbcow):

ok look at it this way SA = 3pir^2 if i plug in A for pir^2 i get SA = 3A

OpenStudy (anonymous):

oh now i got it If Jose used 4 gallons of wood sealant to cover the hemispherical ceiling of his vaction home, how many gallons of wood sealant are needed to cover the floor?

OpenStudy (dumbcow):

ok use what we just learned SA = 3A = 4 gal + gal for the floor

OpenStudy (anonymous):

rid of a and 5 gal

OpenStudy (dumbcow):

sorry i was unclear there we dont know num of gall for the floor, lets call it x

OpenStudy (anonymous):

ok

OpenStudy (dumbcow):

we know SA of top is 2*pir^2 SA = 2pir^2 = 2A

OpenStudy (dumbcow):

2A = 4 gall

OpenStudy (anonymous):

then divide by 2

OpenStudy (anonymous):

A = 2 gal

OpenStudy (dumbcow):

yes

OpenStudy (dumbcow):

total = 3A A = 2 gall so total = 3*2 = 6 gallons

OpenStudy (anonymous):

i got it thank you so much

OpenStudy (dumbcow):

your welcome

OpenStudy (anonymous):

if i need help for my homework can u help me

OpenStudy (dumbcow):

yeah if you post it and im on sure

OpenStudy (anonymous):

thank again ^_^ that help me a lot from you

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