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OpenStudy (anonymous):
OpenStudy (anonymous):
and this
OpenStudy (dumbcow):
hello
for the first one you need to use formula for SA of sphere and then plug in the radius
so
what is SA of a sphere?
what is the radius of our sphere?
OpenStudy (anonymous):
so i have to divide 1.8 by 2
OpenStudy (dumbcow):
correct because radius is half the diameter
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OpenStudy (anonymous):
i got 0.9
OpenStudy (dumbcow):
now substitute that in for r in SA formula
OpenStudy (anonymous):
ok i am doing it right now
OpenStudy (anonymous):
i did the volume then i got 0.972pi
OpenStudy (dumbcow):
correct for volume
i thought we were doing surface area
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OpenStudy (anonymous):
yea but my homework say to find both of them
OpenStudy (dumbcow):
oh ok
what would SA be then
OpenStudy (anonymous):
3.24pi
OpenStudy (dumbcow):
good job
for next one do the same thing except at the end we will divide by 2 because its only half a sphere
OpenStudy (anonymous):
what do you mean?
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OpenStudy (dumbcow):
it shows image of half sphere with radius of 12 right?
so find volume and SA using same formulas substituting 12 for r
but we only want half the volume and half the SA
OpenStudy (anonymous):
i find the volume is 1152pi
OpenStudy (dumbcow):
correct
OpenStudy (anonymous):
SA is 432pi right?
OpenStudy (dumbcow):
no i get 288pi
SA = 4pi*12^2 = 4pi*144 = 576pi
take half of 576
288
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OpenStudy (anonymous):
ok thank here the another question:
The shaded circle at right has area 40π cm2. Find the surface area of the sphere.
OpenStudy (dumbcow):
i dont understand how are the circle and sphere related?
OpenStudy (anonymous):
here the hint:The surface area of a sphere is how many times the area of a circle with the same radius?
OpenStudy (dumbcow):
ok so they share the same radius
is the entire circle shaded?
OpenStudy (anonymous):
here the picture
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OpenStudy (dumbcow):
ok thanks
use area of circle formula to find radius, then plug that into SA formula
A = pi*r^2 = 40pi
OpenStudy (anonymous):
i have to divide pi in both side
OpenStudy (dumbcow):
yes
OpenStudy (anonymous):
i find the raidus 6.32455532
OpenStudy (dumbcow):
correct
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OpenStudy (dumbcow):
SA=4pi*(6.32)^2
OpenStudy (anonymous):
159.7pi
OpenStudy (dumbcow):
correct and you can round up to 160 since we rounded the radius
OpenStudy (anonymous):
Find the volume of a sphere whose surface area is 64π cm2.
OpenStudy (dumbcow):
first find radius
4pi*r^2 = 64pi
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OpenStudy (anonymous):
4
OpenStudy (dumbcow):
good
now use that to find volume
V = 4/3pi*r^3
OpenStudy (anonymous):
i got 256pi over 3
OpenStudy (dumbcow):
correct
OpenStudy (anonymous):
Find the surface area of a sphere whose volume is 288π cm3.
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OpenStudy (dumbcow):
same thing we just did except use volume formula to find radius
V = 4/3pi*r^3 = 288pi
OpenStudy (anonymous):
what should i do with 4/3 pi?
OpenStudy (dumbcow):
well first get rid of pi by dividing pi on both sides like last time
then we will divide by 4/3
OpenStudy (anonymous):
x by 3/4 by both side
OpenStudy (dumbcow):
correct
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OpenStudy (anonymous):
what about 288*3/4
OpenStudy (dumbcow):
think of it as (288*3)/4
OpenStudy (anonymous):
i got 6 as radius
OpenStudy (dumbcow):
correct put that in SA formula
OpenStudy (anonymous):
144pi
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OpenStudy (dumbcow):
correct
OpenStudy (anonymous):
if the radius of the base of a hemisphere (which is bounded by a great circle) is r, what is the area of the great circle? What is the total surface area of the hemisphere, including the base? How do they compare?
OpenStudy (anonymous):
OpenStudy (dumbcow):
you can do this one, its just using the formula for circle area and SA
the radius is just r
OpenStudy (anonymous):
ok i will but i need to leave right but i tell you when i get home
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OpenStudy (dumbcow):
k
OpenStudy (anonymous):
ok i'm back so my homewprk paper has Agreat cicrle=,Shemisphere= and SA Hemisphere=__xA of great circle
OpenStudy (dumbcow):
yes lets fill in the gaps
A = area circle
SA = area circle + 1/2 SA of sphere
OpenStudy (anonymous):
the area of that is pir^2
OpenStudy (dumbcow):
good
A = pir^2
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OpenStudy (anonymous):
we know the radius is r so that mean..
OpenStudy (dumbcow):
whats SA of sphere
OpenStudy (anonymous):
4pir^2
OpenStudy (dumbcow):
good
SA hemishere = pir^2 +(1/2)*4pir^2
add like terms
OpenStudy (anonymous):
3pir^2
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OpenStudy (dumbcow):
good
and A = pir^2 right?
so SA = ___ * A
OpenStudy (anonymous):
what the of Agreat cicrle= and Shemisphere=
OpenStudy (anonymous):
i forgot to put answer
OpenStudy (dumbcow):
A = pir^2
SA hemishere = pir^2 +(1/2)*4pir^2 add like terms
OpenStudy (anonymous):
so that is the answer or i have to solve it
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OpenStudy (dumbcow):
no thats the answer, remember we dont know what r is
OpenStudy (anonymous):
oh ok so SA = r * A
OpenStudy (dumbcow):
well does that sense?
sub in what we know
SA = 3pir^2 and A=pir^2
3pir^2 = r*pir^2
is that true?
OpenStudy (anonymous):
not really
OpenStudy (dumbcow):
ok look at it this way
SA = 3pir^2
if i plug in A for pir^2
i get SA = 3A
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OpenStudy (anonymous):
oh now i got it
If Jose used 4 gallons of wood sealant to cover the hemispherical ceiling of his vaction home, how many gallons of wood sealant are needed to cover the floor?
OpenStudy (dumbcow):
ok use what we just learned
SA = 3A = 4 gal + gal for the floor
OpenStudy (anonymous):
rid of a and 5 gal
OpenStudy (dumbcow):
sorry i was unclear there
we dont know num of gall for the floor, lets call it x
OpenStudy (anonymous):
ok
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OpenStudy (dumbcow):
we know SA of top is 2*pir^2
SA = 2pir^2 = 2A
OpenStudy (dumbcow):
2A = 4 gall
OpenStudy (anonymous):
then divide by 2
OpenStudy (anonymous):
A = 2 gal
OpenStudy (dumbcow):
yes
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OpenStudy (dumbcow):
total = 3A
A = 2 gall
so total = 3*2 = 6 gallons
OpenStudy (anonymous):
i got it thank you so much
OpenStudy (dumbcow):
your welcome
OpenStudy (anonymous):
if i need help for my homework can u help me
OpenStudy (dumbcow):
yeah if you post it and im on sure
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