Question

If r(x)=54x^6-12x^4-27x^3 and t(x)=-9x^3 find
a.) (r/t)(x)
b.)(r/t)(3)
c.)(r/t)(-1)
hope to get some answers and please explain

Answer 1

take the derivative of r(x) with respect to x dr/dx
next take the derivative of dt/dx
use the chain rule dr/dt = dr/dx * dx/dt
that gives you dr/dt

Answer 2

Sorry that makes no sense to me

Answer 3

I think he misread the questions. Assuming I AM reading it right (granted, the notation is a bit weird):

For the first one, just divide r(x) by t(x) (divide each term in r(x) by (-9x^3).

the other two are the same, but with a specific value of x to plug in.

Answer 4

use long division to divide the polynomials

Answer 5

I guess you could call it long division, but it's really just:
\[\frac{54x^6-12x^4-27x^3}{-9x^3} = \frac{54x^6}{-9x^3} + \frac{-12x^4}{-9x^3} + \frac{-27x^3}{-9x^3} = ... \]

Answer 6

I like that better
so how do i apply it to the problem

Answer 7

(Again, this assumed the notation is as I think)

Just find that answer to that (the simplified form).

Then let x = 3 and -1 for the second and third parts, respectively.

Answer 8

so how do i apply it to (r/t)(x)

Answer 9

... That is what (I assume) (r/t)x means...r(x)/r(t)... does it not?

Answer 10

so my answer to (r/t)(x) is: -6^3+4/3x+3

Answer 11

I believe so.

Answer 12

ok i think i got it now