Question

Can someone please help me. I need help "solving the system"

2x+y+z=9
-x-y+z=1
3x-y+z=9

Answer 1

Start off by adding line one and line two; and now you have at least the y disappearing.

Answer 2

I did that. I did it with 1st and 3rd to get 5x+2z=9

Answer 3

Then I went and did it to the 1st and 2nd. Giving me x+2z=10

Answer 4

OK, you have infinitely many choices and your classmates may go about a different way. in x+2z=10 Let z=0. It is your equation you can do what ever you want. So when z=0 in your eq x=10. So x=10, z=0, punch those values in the third eq and solve for y

Answer 5

?? Thanks. sorry, but you lost me.

Answer 6

Its not what our teacher said to do, and I know I will be required to show my work.

Answer 7

The proof is you can plug in the values of x,y,z and see if it equals what is on the other side. Math has a lot of different methods. Tell me specifically what you don't understand.

Answer 8

I came up with (2,1,4) and it fits into the equation. Am I right?

Answer 9

Let's test it with the second equation
-x-y+z=1
-2-1+4=1
1=1
You are exactly right

Answer 10

:)) Yay!!!!!! Thanks!

Answer 11

You can also test them with the others to make sure it wasn't a fluke, but you are doing great.

Answer 12

Now, if I can get the next one...lol!

Answer 13

UGH... This one isnt working out right... Can I explain (the best I know how) what I am doing????

Answer 14

Sorry I had signed out to watch basketball. Hope you figured it out.