find a quadratic formula that has x-intercepts of (2,0) and (-6,0) and has a maximum point of (-2,4)
Okay. write down the standard form of a quadratic equation and post it here.
ax^2+bx=c
ax^2+bx+c
No, it should be y = ax^2+bx +c
alright, now substitute (2,0) and (-6,0) in the equation.
maximum point is arrived at when you take the derivative of y with respect to x and equate it to zero.
whats derivative mean
dy/dx
you shouldn't be doing this problem without learning calculus.
my teacher is an idiot and she doesnt teach us
Oh okay. Well, I can only point you to this: http://www.youtube.com/watch?v=CtRAHmeWSC0
you can also check out khanacademy on youtube. he gives good intro videos on many levels of math
yes. that is right.
You don't need the derivative for this. Just plug in your 3 points into x and y to find 3 linear equations with 3 variables (a, b, and c). Then solve this system of equations to get the coefficients of your quadratic.
It's a system problem, not a calculus one.
lol, yes. polpak is right. sorry.
np. We all have our moments.. For example, I had to be reminded how to integrate odd powers of tan x a few mins ago.
heh. that is true. We all have our moments. :)
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