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Mathematics 13 Online
OpenStudy (anonymous):

find a quadratic formula that has x-intercepts of (2,0) and (-6,0) and has a maximum point of (-2,4)

OpenStudy (anonymous):

Okay. write down the standard form of a quadratic equation and post it here.

OpenStudy (anonymous):

ax^2+bx=c

OpenStudy (anonymous):

ax^2+bx+c

OpenStudy (anonymous):

No, it should be y = ax^2+bx +c

OpenStudy (anonymous):

alright, now substitute (2,0) and (-6,0) in the equation.

OpenStudy (anonymous):

maximum point is arrived at when you take the derivative of y with respect to x and equate it to zero.

OpenStudy (anonymous):

whats derivative mean

OpenStudy (anonymous):

dy/dx

OpenStudy (anonymous):

you shouldn't be doing this problem without learning calculus.

OpenStudy (anonymous):

my teacher is an idiot and she doesnt teach us

OpenStudy (anonymous):

Oh okay. Well, I can only point you to this: http://www.youtube.com/watch?v=CtRAHmeWSC0

OpenStudy (anonymous):

you can also check out khanacademy on youtube. he gives good intro videos on many levels of math

OpenStudy (anonymous):

yes. that is right.

OpenStudy (anonymous):

You don't need the derivative for this. Just plug in your 3 points into x and y to find 3 linear equations with 3 variables (a, b, and c). Then solve this system of equations to get the coefficients of your quadratic.

OpenStudy (anonymous):

It's a system problem, not a calculus one.

OpenStudy (anonymous):

lol, yes. polpak is right. sorry.

OpenStudy (anonymous):

np. We all have our moments.. For example, I had to be reminded how to integrate odd powers of tan x a few mins ago.

OpenStudy (anonymous):

heh. that is true. We all have our moments. :)

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