how do i solve this Y = -16x^2 + 340x + 4500
Solve it for what? Do you mean you have to solve\[-16x^2+340x+4500=0\]?
Or do you have a particular x-value and you need to find y?
Or do you have a y-value and you need to find x?
5200
Are you saying y=5200?
here is the whole problem
Well, it seems reasonable that y=5200 and you need to find the x-values that make it so.
2) Snoopy is in his plane, 4500 feet above the ground. He fires a projectile straight up. The initial velocity of the projectile is 340 feet per second. (After the projectile is fired, it has no acceleration, so its height can be modeled by a “falling body” model.) The Red Baron is maintaining a constant altitude of 5200 feet.
a. Write an equation describing the upward motion of the projectile. (Assume there is no air resistance. Let y represent the altitude of the projectile in feet, and let t represent the time after firing in seconds.) • Y = -16x^2 + 340x + 4500
c. When, on the way up, might the projectile intersect the Red Baron
d. If the projectile misses the Red Baron on the way up, when might it intersect him on the way down?
Is the equation for y an equation you found or were you given that?
i found the equation
Well, the problem will depend on the coordinate system you use. If you 'attach' a coordinate system to Snoopy, then when he fires the projectile straight up, it will look like (in your coordinate system) the object is being fired straight up the y-axis. I'm assuming the Red Barron is directly above Snoopy and travelling with same velocity. Does this agree with you so far?
yes it does
Your equation is correct...so now to finish...
y will be 5200, since your coordinate system is based on the ground, though moving along with Snoopy, so you have to solve for t in:\[5200=-16t^2+340t+4500\]
oh okay
There will be two times: the first is the initial impact, the second when it comes back down. It has the same momentum in the x-direction as Snoopy and the Red Barron.
So there are you answers for c and d.
okay so how do i find out the two times it crosses the red barons path
\[t=\frac{5}{8}(17\pm \sqrt{177})\]
You solve the quadratic equation.
\[5200=-16t^2+340t+4500 \rightarrow -16t^2+340t-700=0\]
\[t = \frac{-340 \pm \sqrt{340^2-4(-16)(-700)}}{2(-16)}=\frac{-340 \pm \sqrt{70800}}{-32}s\]
using the quadratic formula (or you can complete the square).
\[\sqrt{70800}=20\sqrt{177}\]
Then just simplify to get the answers above. The lower time will be the first strike (answer c), the larger time will be the second strike (answer d).
ok
Join our real-time social learning platform and learn together with your friends!