3nth sqrt 50x^2z^5 X 3nth sqrt 15y^3

Question

anonymous · Answer

In this case, it's not so nice because you don't have things you can easily divide. But fractional exponents are valid notationally

anonymous · Answer

So $$\sqrt[3]{a^2} = a^{\frac{2}{3}}$$

anonymous · Answer

well idk if this is right but i got 5sqrt 6yz^2

anonymous · Answer

Wait, the original expression you have is
$$\sqrt[3]{50x^2z^5} \times \sqrt[3]{15y^3}$$
?

anonymous · Answer

yeah. because i broke 50 into radical 25 and and 2

anonymous · Answer

Ok, so yes. If you bring the insides of both together you can factor out a 5 and a z.

anonymous · Answer

So the only problem is that you should have a y and a z on the outside as well.

anonymous · Answer

$$\sqrt[3]{50*15x^2y^3z^5} = \sqrt[3]{6*5^3x^2y^3z^3z^2}$$
And we take out everything with a power of 3.
$$= 5yz*\sqrt[3]{6x^2z^2}$$

anonymous · Answer

ohh. okaiee. that makes sense. thanks once again

anonymous · Answer

All of this is just remembering your rules for exponents when you multiply or raise to a power.
a

$$a^b*a^c = a^{b+c}$$
$$(a^b)^c = a^{b*c}$$